Perl Programming.. How to Use Regular Expressions in your code by prem 10-2-2016.
Qus : Here given one date 2016-02-10. How to convert date-month-year format via perl programming?
(for example 2016-02-10 to 10-02-2016).
$date = "2012-10-02";
if($date =~ m/(\d{4})\-(\d{2})\-(\d{2})/))
{
$year = $1;
$month =$2;
$date = $3;
$converted_date = $date . "-" . $month . "-" . $year;
print "$converted_date\n";
}
----------------------------------program completed-------------------------------------------
Here $1,$2 and $3 is special varibles which contains group values from regular expressions. \d is refers to digits and \d{4} is refers to digits should be contain with 4 digit.
Qus : Here given one date 2016-02-10. How to convert date-month-year format via perl programming?
(for example 2016-02-10 to 10-02-2016).
$date = "2012-10-02";
if($date =~ m/(\d{4})\-(\d{2})\-(\d{2})/))
{
$year = $1;
$month =$2;
$date = $3;
$converted_date = $date . "-" . $month . "-" . $year;
print "$converted_date\n";
}
----------------------------------program completed-------------------------------------------
Here $1,$2 and $3 is special varibles which contains group values from regular expressions. \d is refers to digits and \d{4} is refers to digits should be contain with 4 digit.
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